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3y^2-90y=0
a = 3; b = -90; c = 0;
Δ = b2-4ac
Δ = -902-4·3·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-90}{2*3}=\frac{0}{6} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+90}{2*3}=\frac{180}{6} =30 $
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